In the circuit current through source will be
[Given `(cos^(-1) (0.6) = 53^(@))]`
`V = 10 + 10 sqrt(2) sin (100 pi + 45^(@))`

.In the circuit current through source will be: [Given (cos^(-1)(0.6)=53degree

In a circuit, the instantaneous values of alternating current and voltages in a circuit is given by I = (1)/(sqrt2) sin (100 pi t) A and E = (1)/(sqrt2) sin (100 pi t + (pi)/(3)) V . The average power in watts consumed in the circui is

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The instantaneous values of alternating current and voltages in a circuit are given as [i=(1)/(sqrt(2))sin(100 pi t) ampere e=(1)/(sqrt(2))sin(100 pi t+pi/3) Volt.The average power in Watts consumed in the circuit is

In the circuit shown the source voltage is given as v = V_(0) sin omegat . Find the current through the source as a function of time.