A body is projected horizontally from the top of a tower with initial velocity `18 m s^-1`. It hits the ground at angle `45^@`. What is the vertical component of velocity when it strikes the ground ?

A body is projected horizontally from the top of a tower with a velocity of 10m/s. If it hits the ground at an angle of 45^@ , the vertical component of velocity when it hits ground in m/s is

A body is projected horizontally from the top of a tower with a velocity of 10 m//s .If it hits the ground at an angle 45^(@) , then vertical component of velocity when it hits ground in m//s is

A body is projected horizontally from the top of a tower with a velocity of 10 m//s .If it hits the ground at an angle 45^(@) , th vertical component of velocity when it hits ground in m//s is

[" A body is projected "],[" horizontally from the "],[" top of a tower with "],[" initial velocity "9m/s" ."],[" It hits the ground at "],[" angle "45^(@)." What is "],[" the vertical "],[" component of "],[" velocity in "m/s" when "],[" it strikes the ground? "]

A body is projected horizontally from the top of a tower with a velocity of 20 m/s. After what time the vertical component of velocity is four times the horizontal component of velocity ? (g = 10 m//s^(2) )