9 articles are to be placed in 9 boxes one in each box. 4 of them are too big for three of the boxes. The number of possible arrangements is.

9articles are to be placed in 9 boxes one in each box.4 of them are too big for three of the boxes.The number of possible arrangements is.

7balls (distinct) are to be placed in 7 boxes (distinct) and 4 of the balls can not fit into 2 small boxes.The number of ways of arranging one ball in each of the boxes is X .Let P be the probability of selected divisor in the list of divisors of X is in the Form of 4n+1 ,then find 6P (where n in N)

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes.the number of ways of arranging one ball in each of the boxes is

The digits, from 0 to 9 are written on 10 slips of paper (one digit on each slip) and placed in a box. If three of the slips are drawn and arranged, then the number of possible different arrangements is

The digits, from 0 to 9 are written on 10 slips of paper (one digit on each slip) and placed in a box. If three of the slips are drawn and arranged, then the number of possible different arrangements is

9 balls are to placed in 9 boxes : and 5 of the balls cannot fit into 3 small boxes the number of ways of arranging one ball in each of the boxes is