A wire `(Y=2xx10^(11)N//m` has length 1m and area `1mm^(2)`. The work required to increase its length by 2mm is

A wire (Y =2xx10^11N//m^2) has length 1m and area 1mm^2 . Calculate the work required to increase its length by 2mm.

A certain force increases the length of a wire by 1 mm. The force required to increases its length by 2 mm is …………… .

Length and cross sectional area of a wire are 5 m and 2.5 mm^(2). Calculate work required to be done to increase its length by 1 mm. Young's modulus of material of wire =2 xx 10 ^(11) Nm ^(-2)

The Young's modulus of a wire of length 2m and area of cross section 1 mm^(2) is 2 xx 10^(11) N//m^(2) . The work done in increasing its length by 2mm is

The area of cross - section of a wire is 1" mm"^(2) and it length is 2 m. How much work will be done to increase its length by 0.1 mm ? The Young.s modulus of elaticity for the material of the wire is 2xx10^(11)" Nm"^(-2) .

The area of cross section of a steel wire (Y=2.0xx10^11 N//m^2) is 0.1 cm^2 . The force required to double its length will be

The young's modulus of a wire of length 2m and area of cross section 1mm^2 is 2 xx 10^10 N/m^2 . What is the work done in increasing it's length by 2mm.

A wire of length 1m and area of cross section 4 xx 10^(-8) m^(2) increases in length by 0.2 cm when a force of 16 N is applied. Value of Y for the material of the wire will be

What should be the weight suspended from the end of a steel wire 2 m in length and w mm in diameter to increase the length by 1 mm ? (Y=19xx10^(11)N//m^(2))