A force `F = Be^(Ct)` acts on a particle whose mass is m and whose velocity is 0 at t = 0. It's terminal velocity is :

What is the velocity of particle whose mass is double that of rest mass?

A force vecF = 6t^(2)hat i +4thatj is acting on a particle of mass 3 kg, then what will be velocity of particel at t = 3 sec if at t = 0, particle is at rest :

Obtain an expression for the centripetal force F acting on a particle of mass m moving with velocity v in a circle of radius r . Take dimensionless constant K = 1 .

A time varying force, F=2t is acting on a particle of mass 2kg moving along x-axis. velocity of the particle is 4m//s along negative x-axis at time t=0 . Find the velocity of the particle at the end of 4s.

A time varying force, F=2t is acting on a particle of mass 2kg moving along x-axis. velocity of the particle is 4m//s along negative x-axis at time t=0 . Find the velocity of the particle at the end of 4s.

A force vecF=6t^(2)hati+4thatj is acting on a particle of mass 3 kg then what will be velocity of particle at t=3 second and if at t=0, particle is at rest:-

A force vecF=6t^(2)hati+4thatj is acting on a particle of mass 3 kg then what will be velocity of particle at t=3 second and if at t=0, particle is at rest:-