Volume of parallelepiped determined by vectors `bara,barb` and `barc` is 5.
Then the volume of the parallelepiped determined by the vectors `3(bara +barb). (barb + barc)` and 2(`barc + bara)` is

Volume of parallelopiped determined by vectors bara and barb and barc is 2. Then the volume of the parallelepiped determined by vectors 2 (bara xx barb), 3 (barb xx barc) and (barc xx bara) is

If [barabarb barc] = 3 , then the volume (in cu. u.) of the parallelepiped with 2bara + barb, 2barb + barc and 2barc + bara as coterminus edges is

If V is the volume of the parallelopiped having three coterminous edge, as, bara ,barb and barc then the volume of the parallopiped having three coterminous edges as baralpha=(bara.bara)bara+(bara.barb)barb+(bara.barc)barc barbeta=(barb.bara)bara+(barb.barb)barb+(barb.barc)barc bargamma=(barc.bara)bara+(barc.barb)barb+(barc.barc)barc is

[bara barb barc]+[bara barc barb] =

The volume of parallelopiped with vector bara+2barb-barc,bara-barb and bara-barb-barc is equal to k[bar(a)bar(b)bar(c)] then k=

The volume of parallelopiped with vector bara+2barb-barc,bara-barb and bara-barb-barc is equal to k[bar(a)bar(b)bar(c)] then k=

For any three vectors bara, barb, barc prove : [bara-barb, barb-barc, barc-bara]=0

For any three vectors bara,barb and barc,(bara-barb) .[(barb+barc)xx(barc+bara)] is equal to:

(bara+2barb-barc).(bara-barb)xx(bara-barb-barc)=