At `627^(@)C` and `1` atm `SO_(3)` is partially dissociated into `SO_(2)` and `O_(2)` by the reaction
`SO_(3)(g)hArrSO_(2)(g)+1//2O_(2)(g)`
The density of the equilibrium mixture is `0.925 g L^(-1)`. What is the degree of dissociation?

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?

At 727^(@)C and 1.2 atm of total equilibrium pressure, SO_(3) is partially dissociated into SO_(2) and O_(2) as: SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g) The density of equilibrium mixture is 0.9 g//L . The degree of dissociation is:, [Use R=0.08 atm L mol^(-1) K^(-1)]

At 727^(@)C and 1.2 atm of total equilibrium pressure, SO_(3) is partially dissociated into SO_(2) and O_(2) as: SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g) The density of equilibrium mixture is 0.9 g//L . The degree of dissociation is:, [Use R=0.08 atm L mol^(-1) K^(-1)]

The reaction SO_(2)(g) +1//2O_(2)(g) rarr SO_(3)(g) should be

The reaction SO_(2)(g) +1//2O_(2)(g) rarr SO_(3)(g) should be

SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g) If observed vapour density of mixture at equilibrium is 35 then find out value of alpha

SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g) If observed vapour density of mixture at equilibrium is 35 then find out value of alpha