" If the derivative of tan "^(-1)(a+bx)" takes the value "1" at "x=0," prove that "1+a^(2)=b

If the derivative of tan^(-1)(a+b x) takes the value 1 at x=0 , prove that 1+a^2=b .

If the derivative of tan^(-1)(a+b x) takes the value 1 at x=0, prove that 1+a^2=bdot

If the derivative of tan^(-1)(a+bx) take the value of 1 at x=0 ,prove that 1+a^(2)=b

If the derivative of tan^(-1)(a+b x) take the value of 1 at x=0, prove that 1+a^2=bdot

If the derivative of tan^(-1) (a + bx) takes the value 1 at x= 0, the 1 +a^(2)=

If the derivative of tan^(-1)(a+bx) takes the value (dy)/(dx)=1 at x=0 , then prove that b=1+a^(2)

IF the derivative of tan ^(-1)(a + bx) w.r.t.x takes the value 1 at x= 0, write the relationship between a and b.

If the derivative of tan ^(-1)(a+bx) at x=0 is 1, then 1-b^(3)+a^(6)

Find the derivative of : y = 2tan^-1 sqrtfrac(x-a)(b-x)