Calculate enthalpy change of the following reaction `:`
`H_(2)C=CH_(2(g))+H_(2(g)) rarr H_(3)C-CH_(3(g))`
The bond energy of `C-H,C-C,C=C,H-H` are `414,347,615` and `435k J mol^(-1)` respectively.

Calculate enthalpy change of the following reaction : CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3) - CH_(3)(g) The bond energy of C - H, C - C, C = C, H - H are 414,347, 615 and 436 kJ mol^(-1) respectively.

Calculate enthalpy change of the following reaction : CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3) - CH_(3)(g) The bond energy of C - H, C - C, C = C, H - H are 414, 615 and 436 kJ mol^(-1) respectively.

Calculate the enthalpy of the following reaction : CH_2= CH_2 (g) + H_2(g) to CH_3 - CH_3(g) The bond energies of C-H, C-C, C=C and H-H bonds are 414, 347, 615 and 435 kJ mol^(-1) respectively.

Calculate the enthalpy of the following reaction: H_(2)C =CH_(2)(g) +H_(2)(g) rarr CH_(3)-CH_(3)(g) The bond energies of C-H, C-C,C=C , and H-H are 99,83,147 ,and 104kcal respectively.

Calculate the enthalpy of the following reaction: H_(2)C =CH_(2)(g) +H_(2)(g) rarr CH_(3)-CH_(3)(g) The bond enegries of C-H, C-C,C=C , and H-H are 99,83,147 ,and 104kcal respectively.