An object of mass 2 kg at rest at origin starts moving under the action of a force
`vec(F)=(3t^(2)hat(i)+4that(j))N` The velocity of the object at t = 2 s will be -

A particle of mass 2 kg moves in the xy plane under the action of a constant force vec(F) where vec(F)=hat(i)-hat(j) . Initially the velocity of the particle is 2hat(j) . The velocity of the particle at time t is

A particle of mass 2 kg moves in the xy plane under the action of a constant force vec(F) where vec(F)=hat(i)-hat(j) . Initially the velocity of the particle is 2hat(j) . The velocity of the particle at time t is

An object is moving along a straight line path from P to Q under the action of force vec(F)=(4hat(i)-3hat(j)+2hat(k))N . If the co - ordinate of P & Q in metres are (3,2,-1) & (2,-1,4) respectively. Then the work done by the force is :

A body of mass 1 kg begins to move under the action of a time dependent force vec(F) =(2t hat(i)+3t^(2)hat(j)) N . Where hat(i) and hat(j) are unit vectors along X and Y axis . What power will be developed by the force at the time t .

An object of mass 3 kg is at rest . Now a force F= 6t^(2) hati + 2thatj is applied on the object . Find the velocity of the object at t =3 sec.

An object of mass 3 kg is at rest . Now a force F= 6t^(2) hati + 2thatj is applied on the object . Find the velocity of the object at t =3 sec.

A body under the action of a force vec(F)=6hat(i)-8hat(j)N acquires an acceleration of 5ms^(-2) . The mass of the body is