The equation of the image of the circle `x^2 +y^2-6x-4y +12 = 0` by the mirror `x+y-1=0` is

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the line mirror x+y-1=0 is

Find the equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the line mirror x+y-1=0

Find the equation of the image of the circle : x^2 + y^2 + 8x-16y + 64=0 in the mirror x = 0.

Find the equation of the image of the circle x^2+y^2+8x-16y+64=0 in the line mirror x=0.

Find the equation of the tangent to the circle x^2+y^2-4x-6y-12=0 at (-1,-1)

The equation of the normal at (1,2) to the circle x^(2)-y^(2)-4x-6y-12=0 is

The equation of the normal to the circle x^(2)+y^(2)+6x+4y-3=0 at (1,-2) to is

The equation of the normal to the circle x^(2)+y^(2)+6x+4y-3=0 at (1,-2) to is

The equation of the circle concentric with the circle x^(2) + y^(2) - 6x - 4y - 12 =0 and touching y axis

The equation of the circle is 3x^(2) + 3y^(2)+6x-4y -1=0 . Then its radius is