The inverse of the point (1, 2) with respect to circle `x^2+y^2-4x-6y+9=0`

The inverse of the point (1, 2) with respect to the circle x^(2) + y^(2) - 4x - 6y + 9 = 0 is

The inverse of the point (1, 2) with respect to the circle x^(2) + y^(2) - 4x - 6y + 9 = 0 is

The value of a, such that the power of the point (1, 6) with respect to the circle x^(2)+y^(2)+4x-6y-a=0" is -16 is"

Find the inverse point of (-2,3) with respect to the circle x^(2)+y^(2)-4x-6y+9=0

Find the inverse point of (-2,3) with respect to the circle x^(2)+y^(2)-4x-6y+9=0

Determine the positions of the points (-1, 2) with respect to the circle x^(2) + y^(2) - 4x + 6y + 4 = 0 .

Find the polar of the point (-2,3) with respect to the circle x^2+y^2−4x−6y+5=0

Determine the positions of the points (1, -1) with respect to the circle x^(2) + y^(2) - 4x + 6y + 4 = 0 .

Determine the positions of the points (-1, -3) with respect to the circle x^(2) + y^(2) - 4x + 6y + 4 = 0 .

Locate the position of the point (2,4) with respect to the circle. x^(2)+y^(2)-4x-6y+11= 0