36g of glucose (molar mass = `180 g//mol)` is present in 500g of water, the molarity of the solution is

2.82g of glucose (molar mass =180 ) is dissolved in 30g of water. Calculate the (i) Molality of the solution (ii) mole fractions of (a) glucose (b) water.

2.82g of glucose (molar mass =180 ) is dissolved in 30g of water. Calculate the (i) Molality of the solution (ii) mole fractions of (a) glucose (b) water.

If 180 g of glucose is present in 400 ml of solution, molarity of the solution is:

4.5g mass of a substance (molar mass = 90g/mol) is dissolved in 250ml solution, the molarity of solution is

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is

18g of glucose (molar mass 180g "mol"^(-1) ) is present in 500CM^(3) of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

18g of glucose (molar mass 180g "mol"^(-1) ) is present in 500CM^(3) of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is:

18g of glucose (molar mass 180gmol^-1) is present in 500cm^3 of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?