If `f : R -> R` and `g : R -> R` defined `f(x)=|x|` and `g(x)=[x-3]` for `x in R` [.] denotes the greatest integer function

If f:R rarr R and g:R rarr R defined f(x)=|x| and g(x)=[x-3] for x in R[.] denotes the greatest integer function

If f(x) = [x] - [x/4], x in R where [x] denotes the greatest integer function, then

If f:R rarr R are defined by f(x)=x-[x] and g(x)=[x] for x in R, where [x] is the greatest integer not ex-ceeding x, then for everyx in R,f(g(x))=

If f: R to R is defined by f(x)=x-[x]-(1)/(2) for all x in R , where [x] denotes the greatest integer function, then {x in R: f(x)=(1)/(2)} is equal to

If f:R rarr R and g:R rarr R are defined by f(x)=x-[x] and g(x)=[x] is x in R then f{g(x)}

f:R rarr R,g:R rarr R are defined as f(x)=|x|,g(x)=[x]AA x in R[*] is denotes greatest integer function then {x in R:g[f(x)]<=f[g(x)]}=

Let f:R rarr A defined by f(x)=[x-2]+[4-x], (where [] denotes the greatest integer function).Then

If f: R to R is function defined by f(x) = [x-1] cos ( (2x -1)/(2)) pi , where [.] denotes the greatest integer function , then f is :

Find gof and fog when f: R->R and g: R->R is defined by f(x)=x and g(x)=|x|

If f(x)=2[x]+cos x, then f:R rarr R is: (where [] denotes greatest integer function)