Rectangle ABCD has sides AB=a,BC=24 .If point P on BC internally divides it 2:1 and `tan(/_APD)=3` ,then the value of 'a' is

ABCD is a rectangle with sides AB=p,BC=q. If AB and AD are taken as negative directions of coordinate axes,then the equation of the circle circumscribing the rectangle is

ABCD is a rectangle with sides AB=p,BC=q. If AB and AD are taken as negative directions of coordinate axes,then the equation of the circle circumscribing the rectangle is

ABCD is a rectangle in which AB=10cms,BC=8cms.A point P is takes on AB such that PA=x Then the minimum value of PC^(2)-PD^(2) is obtained when x=

In a rectangle ABCD, AB= 15 cm angle BAC = 60^@ then BC is equal to

ABCD is a rectangle in which AB= 9cm, BC=6cm. P is a point in CD such that PC = xcm, then the value of x when AP^2 + BP^2 is minimum is

In DeltaABC , P is the mid point of BC,Q divides CA internally in the ratio 2:1 and R divides AB externally in the ratio 1:2 then

Construct a rectangle ABCD whose sides AB=5.4 cm and BC=4.5cm.

In the given figure,ABCD is a rectangle in AB-40cm and BC=25cm. If P,Q,R,S be the mid-points of the sides AB,BC,CD and DA respectively,find the area of the shaded region.