Two Radioactive substances X and Y emit a and B particles respectively. Their disintegration constants are in the ratio 2 : 3. To have equal rate of disintegration of getting emission of a and particles, the ratio of number of atoms of X to that of Y at any time instant is

There are two radio-active nuclei A and B . A in an alfa-emitter while B is a beta-emitter, Their disintegration constant are in the ratio of 1:4 . The ratio of number of nuclei of A and B at any time 't' such that probabilities of getting number of alpha and beta particles are same at the instant is y:1 . Then y ______is

The rate of disintegration of a radioactive substance is …………………………… to the number of atoms present at that time .

There are two radio nuceli A and B. A is an alpha emitter and B a beta emitter. Their disintegration constant are in the ratio of 1:2 What should be the ratio of number of atoms of A and B at any time t so that probabilities of getting alpha and beta particles are same at that instant?

Two radioactive substances X and Y initially contain an equal number of atoms. Their half-lives are 1 hour and 2 hours respectively. Then the ratio of their rates of disintergration after two hours is

In a radioactive disintegration, the ratio of initial number of atoms to the number of atoms present at an instant of time equal to its mean life is

Two radioactive substances are having same initial number of nuclei. Disintegration constant of one substance is 10lamda , other one lamda after how much time ratio of number of nuclei becomes (1)/(e) ?

The radioactive sources A and B of half lives of 2 hr and 4 hr respectively, initially contain the same number of radioactive atoms. At the end of 2 hours, their rates of disintegration are in the ratio :

The radioactive sources A and B of half lives of t hr and 2t hr respectively, initially contain the same number of radioactive atoms. At the end of t hours, their rates of disintegration are in the ratio: