The rate constant for the reaction:
`2N_(2)O_(5) rarr 4NO_(2)+O_(2)` is `3.0xx10^(-5) sec^(-1)`. If the rate is `2.40xx10^(-5) M sec^(-1)`, then the concentration of `N_(2)O_(5)` (in M) is:`

The rate constant for the reaction 2N_(2)O_(5) rarr 4NO_(2)+O_(2) is 3.0 xx 10^(-5) s^(-1) . If the rate is 2.40 xx 10^(-5) mol L^(-1) s^(-1) , then the concentration of N_(2)O_(5) (in mol L^(-1) ) is

The rate constant for the reaction, 2N_(2)O_(5) rarr 4NO_(2) + O_(2) is 3.0 xx 10^(-5) s^(-1) . If the rate is 2.40 xx 10^(-5) mol L^(-1) s^(-1) , then the initial concentration of N_(2)O_(5) (in mol L^(-1) ) is

The rate constant for the reaction 2N_(2)O_(5)to4NO_(2)+O_(2), "is"" " 3.0xx10^(-5)S^(-1) . If the rate is 2.40xx10^(-5)"mol"L^(-1)s^(-1) then the concentration of N_(2)O_(5)("in mol" L^(-1)) is

The rate constant for the reaction, 2N_2O_5 to 4NO_2 + O_2" is "4.0 xx 10^(-5)sec^(-1) . If the rate is 3.4 xx 10^(-5)mol.l^(-1)s^(-1) . Then the concentration of N_2O_5 (in mol litre^(-1) ) is :

Rate constant for the reaction 2N_(2)O_(5) to 4NO_(2) + O_(2) is 4.98 xx 10^(-4) s^(-1) . Find the order of reaction?

The rate constant for the reaction 2N_(2)O_(5)rarr 4NO_(3)+O_(2) is 3.0 xx10^(-4)s^(-1) . If start made with 1.0 mol L^(-1) of N_(2)O_(5) . Calculate the rate of formation of NO_(2) at the moment of the reaction when concentration of O_(2) is 0.1 mol L^(-1)