If the eccentricity of the ellipse,`x^2/(a^2+1)+y^2/(a^2+2)=1` is `1/sqrt6` then latus rectum of ellipse is

If the eccentricity of the ellipse,(x^(2))/(a^(2)+1)+(y^(2))/(a^(2)+2)=1 is (1)/(sqrt(6)) then latus rectum of ellipse is

Suppose the eccentricity of the ellipse x^2/(a^2+3)+ y^2/(a^2+4)=1 is 1//sqrt8 . Let l be the latus rectum of the ellipse, then l equals

If eccentricity of the ellipse (x^(2))/(a^(2)+1)+(y^(2))/(a^(2)+2)=1 is (1)/(sqrt6) , then the ratio of the length of the latus rectum to the length of the major axis is

the eccentricity of an ellipse (x^(2))/(a^(2))+(y^(2))=1 whose latus rectum is half of its minor axes , is