In triangle `A B C` , the equation of the right bisectors of the sides `A B` and `A C` are `x+y=0` and `y-x=0` , respectively. If `A-=(5,7)` , then find the equation of side `B Cdot`

In triangle ABC, the equation of the right bisectors of the sides AB and AC are x+y=0 and y-x=0, respectively.If A-=(5,7), then find the equation of side BC.

In triangle ABC, the equation of the right bisectors of the sides AB and AC are x+y=0 and y-x=0. respectively. If A-=(5,7) the find the equation of side BC.

In Delta ABC equation of the right bisectors of the sides Ab and AC are x+y = 0 and x - y = 0 respectively .If A = (5,7) then equation of side BC is

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .