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A long horizontal slit is placed 1 mm ab...

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

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A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 m away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 in away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

Consider the situation of the previous problem, if the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen ?

Consider the situation of the previous problem, if the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen ?

Consider the situation of the previous problem, if the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen ?

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The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :