If displacement S at time t is `S=t^(3)-3t^(2)-15t+12`, then acceleration at time `t=1 sec` is

If displacement S at time t is S=-t^(3)+3t^(2)+5 , then velocity at time t=2 sec is

If S=t^(3)-64t-8 , then acceleration vanishes at time t=

If displacement S at time t is S=10t-5t^(2) , then velocity at time t is

Equation of displacement for any particle is s = 3t^(3) +7t^(2) +14t8m . Its acceleration at time t = 1 sec is

If displacement S at time t is S=2t^(3) +6t , then velocity is always

Displacement x at time t is x=t-t^(3) . If v is the velocity and a the acceleration at time t, then :v =

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

Function of displacement x and time t is defined by equation x=2t^(3)-3t^(2)-4t+1 . Acceleration will be zero at time

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is