A block of mass 1 kg is placed on a rough wedge which is fixed on an elevator going upward with acceleration `2 ms^(-2)`. The block is a rest with respect to the wedge.

Select the correct alternative ( take ` g = 10 ms^(-2) ` )

A block of mass m is at rest over the rough surface of the fixed wedge.

The acceleration of block is( g=10 ms-2)

In the adjoining figure a wedge is fixed to an elevator moving upwards with an acceleration a . A block of mass m is placed over the wedge.Find the acceleration of the block with respect to wedge. Neglect friction

In the adjoining figure a wedge is fixed to an elevator moving upwards with an acceleration a . A block of mass m is placed over the wedge.Find the acceleration of the block with respect to wedge. Neglect friction

A small block of mass 1 kg is kept on a rough inclined wedge of inclination 45^@ fixed in an elevator. The elevator goes up with a uniform velocity v=2 m//s and the block does not slide on the wedge. Find the work done by the force of friction on the block in 1s . (g=10 m//s^(2))

A small block of mass 1 kg is kept on a rough inclined wedge of inclination 45^@ fixed in an elevator. The elevator goes up with a uniform velocity v=2 m//s and the block done not slide on the wedge. Find the work done by the of friction on the block in 1s . (g=10 m//s^(2))

A block of mass 1 kg is placed on a wedge shown in figure. Find out minimum coefficient of friction between wedge and block to stop the block on it.

If the elevator in shown figure is moving upwards with constant acceleration 1 ms^(-2) , tension in the string connected to block A of mass 6 kg would be ( take, g =10 ms^(-2) )

If the elevator in shown figure is moving upwards with constant acceleration 1 ms^(-2) , tension in the string connected to block A of mass 6 kg would be ( take, g =10 ms^(-2) )

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5 m//s^(-2) .Let N be the normal reation between the block and the wedge . Then (g = 10 m//s^(-2))