If `18` is subtracted from the present age of mayank's age the two digits of his reverse their positions.Also his age is six less than `8` times the sum of digits of his present age. Find Mayank's present age :

Ten years ago, Mohan's age was 35 years less than twice his present age. Find Mohan's present age (in years)

Thirty years ago, the age of a man was three-fifth of his present age. Find the present age (in years)

If 6 years are subtracted from the present age of Panas and take 25% of that then we get the present age of his only son. 4 years ago, his daughter's age is 7 years more than his son. Sum of daughter's present age and his wife's present age is 10 years more than Panas's present age , then find the present age of Panas if average of present age of entire family is 30.25 years ?

The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their present ages.

The age of a man is twice the sum of the age of his two children . After 20 years his age will be equal to the sum of the age of his children, at that time. Find the present age of the sum.

A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages. Find the present age of the father.

A father's age is three times the sum of the ages of his two children. After 5 years his age will be 2 times the sum of their ages. Find the present age of the father.

Two years ago, a man's age was three times the square of his son's age. In three years time, his age will be four times his son's age. Find their present ages.