एक संधारित्र को परावैद्युतांकों द्वारा चित्रानुसार भरा गया है | परिणामी धारिता होगी

Options

A. `(epsilon_(0)A)/(d)[(1)/(K_(1))+(1)/(K_(2))+(1)/(K_(2))]`
B. `(epsilon_(0)A)/(d)[(1)/(K_(1))+(1)/(K_(2))+(1)/(K_(3))]`
C. `(2epsilon_(0)A)/(d)[K_(1)+K_(2)+K_(3)]`
D. इनमें से कोई नहीं

Answer

D

Explanation

`C_(1)=(K_(1)epsilon_(0)(A)/(2))/(((d)/(2)))=(K_(1)epsilon_(0)A)/(d)`
`C_(2)=(K_(2)epsilon_(0)((A)/(2)))/(((d)/(2)))=(K_(2)epsilon_(0)A)/(d)` एवं `C_(3)=(K_(3)epsilon_(0)A)/(2d)=(K_(3)epsilon_(0)A)/(2d)`
अतः `C_(eq)=C_(3)+(C_(1)C_(2))/(C_(1)+C_(2))=((K_(3))/(2)+(K_(1)K_(2))/(K_(1)+K_(2))).(epsilon_(0)A)/(d)`