यदि `""_(92)U^(238)` क्रमशः `8alpha`-क्षय तथा `6beta`-क्षय से गुजरता है | तो परिणामी नाभिक है

Options

A. `""_(82)U^(206)`
B. `""_(82)Pb^(206)`
C. `""_(82)U^(210)`
D. `""_(82)U^(214)`

Answer

B

Explanation

`""_((Z=92))U^((A=238))overset((8alpha,6beta))rarr ""_(Z.)X^(A.)`
इसलिए `A.=A-4n_(alpha)=238-4xx8=206`
एवं `Z.=n_(beta)-2n_(alpha)+z=6-2xx8+92=82`.