An iron ball of diameter `6cm` and is `0.01 mm` too large to pass through a hole in a brass plate when the ball and plate are at a temperature of `20^(0)C`. The temperature at which (both for ball and plate) the ball just passes through the hole is
`(alpha_(iron) = 12 xx 10^(-6 //0)C, alpha_(brass) = 18 xx 10^(-6 //0)C)`

An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 20^(@) C . The temperature at which (both for ball and plate) the ball just pass through the hole is (alpha_("iron") = 12 xx 10^(-6) //1^(@) C, alpha_("brass") = 18 xx 10^(-6) //1^(@) C)

An iron ball has a diameter of 6 cm and is 0.010 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 30^@ C . At what temperature, the same for ball and plate, will the ball just pass through the hole? Take the values of (prop) from Table 20 .2 .

An iron ball has a diameter of 6 cm and is 0.010 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 30^@ C . At what temperature, the same for ball and plate, will the ball just pass through the hole? Take the values of (prop) from Table 20 .2 .

An iron ball (coefficient of linear expansion =1.2xx(10^(-5)//^(@)C ) has a diameter of 6 cm and is 0.010 mm too large to pass through a hole in a brass plate (coefficient of linear expansion =1.9xx10^-5//^(@)C ) when the ball and the plate are both at a temperature of 30^@C At what common temperature of the ball and the plate will the ball just pass through the hole in the plate ?

A metal sphere 10.01 cm in diameter is placed on a brass ring of internal diameter 10 cm at the same temperature of 12^@C . Find the temperature to which they should be heated together so that the metal sphere just passes through the ring . alpha_"metal" = 12 xx 10^(-6)//^@C and alpha_"brass" = 18 xx 10^(-6)//^@C

A metal sphere 10.01 cm in diameter is placed on a brass ring of internal diameter 10 cm and at the same temperature of 10^@C . The temperature up to which they should be heated together so that the metal sphere just passes through the ring is [alpha_(me ta l)= 12 xx 10^-6/@C and alpha_brass= 18 xx 10^-6/@C]

A cylindrical steel plug is inserted into a circular hole of diameter 2.60 cm in a brass plate. When the plug and the plates are at a temperature of 20^(@)C, the diameter of the plug is 0.010 cm smaller than that of the hole. The temperature at which the plug will just fit in it is ("Given",alpha_(steel)=11xx10^(-6)C^(-1)and alpha_(brass)=19xx10^(-6)C^(-1)