A mercury drop of radius 1 cm is broken into `10^6` droplets of equal size. The work done is `(T=35xx10^-2(N)/(m)`)

If a mercury drop of radius 1 cm is broken into a million of equal size, then the work done will be (T=35xx10^-2N//m)

A mercury drop of radius lcm is sprayed into 10^6 droplets of equal size. If surface tension of mercury is 35 xx 10^(-3) N/m. The energy expended is 4.36 xx 10^(-n) J Find n

A mercury drop of radius 1.0 cm is sprayed into 10^(6) droplets of equal sizes. The energy expended in this process is (Given, surface tension of mercury is 32 xx 10^(-2) Nm^(-1) )

A mercury drop of radius 1.0 cm is sprayed into 10^(6) droplets of equal sizes. The energy expended in this process is (Given, surface tension of mercury is 32 xx 10^(-2) Nm^(-1) )

A mercury drop of radius 1 cm is sprayed into 10^(6) droplets of equal size. Calculate the energy expended if surface tension of mercury is 35xx10^(-3)N//m .

A mercury drop of radius 1 cm is sprayed into 10^(6) dropletes of equal size. Calculates the energy expanded if surface tension of mercury is 35 xx 10^(-3) N//m .

A mercury drop of radius 1 cm is sprayed into 10^6 drops of equal size. The energy expended in joule is (Surface tension of mercury is 460 xx10 N m^-1 )

A mercury drop of radius 1 cm is sprayed into 10^(6) drops of equil size. The energy expended in joule is (surface tension of mercury is (460xx10^(-3)N//m)