A ball is thrown such that the time of flight is `5 s` and the horizontal range is `200 m`. Find the magnitude and direction of velocity of projection.

A ball is thrown at an angle theta with the horizontal. Its time of flight is 2 s. Its horizontal range is 100 m. What is the horizontal component of velocity of projection ? Take g =10 ms^(-2) .

Time of flight is 1 s and range is 4 m .Find the projection speed is:

An arrow is shot in air, its time of flight is 5 sec and horizontal range is 200 m. the inclination of the arrow with the horizontal is

An arrow is shot in air, its time of flight is 5 sec and horizontal range is 200 m. the inclination of the arrow with the horizontal is

Time of flight is 15 m and range is 4 m .Find the projection speed is:

A particle is thrown with a velocity 10 m//s and its horizontal range is 5 m . Find angle/angles of the projection.

A javelin thrown into air at an angle with the horizontal has a range of 200 m. If the time of flight is 5 second, then the horizontal component of velocity of the projectile at the highest point of the trajectory is

A javelin thrown into air at an angle with the horizontal has a range of 200 m. If the time of flight is 5 second, then the horizontal component of velocity of the projectile at the highest point of the trajectory is