If a planet rotates too fast, rocks from its surface will start flying off its surface. If density of a homogeneous planet is `rho`and material is not flying off its surface then show that ts time period of rotation must be greater then `sqrt((3pi)/(Gp))`

If the density of a planet is constant, then the curve between value of g on its surface and its radius r will be-

If the density of a planet is constant, then the curve between value of g on its surface and its radius r will be-

If the radius of a planet is R and its density is rho , the escape velocity from its surface will be

Derive an expression for time period of a satellite orbiting very close to earth's surface in terms of mean density OR A satellite is in a low-altitude circular orbit around a spherical planet of mean density rho . Show that the period of revolution of the satellites is sqrt(3pi//rhoG)

If a new planet is discovered rotating around Sun with the orbital radius double that of earth, then what will be its time period (in earth's days)

If a new planet is discovered rotating around Sun with the orbital radius double that of earth, then what will be its time period (in earth's days)

Show that the object lying at the equator will fly off the surface of earth, if the speed of rotation of the earth increase seventeen times its present speed.

The fastest possible of rotation of a planet is that for which the gravitational force on material at the equtor barely provides the centripetal force needed for the rotation. Show then that the corresponding shortest period of rotation is given by T=sqrt((3pi)/(Grho)) where rho is the density of the planet, assumed to be homogeneous. Evalute the rotation period assuming a density of 3.0 gm//cm^(2) , typical of many planets, satellites, and asteroids. No such object is found to be spinning with a period shorter than found by this analysis.

The fastest possible of rotation of a planet is that for which the gravitational force on material at the equtor barely provides the centripetal force needed for the rotation. Show then that the corresponding shortest period of rotation is given by T=sqrt((3pi)/(Grho)) where rho is the density of the planet, assumed to be homogeneous. Evalute the rotation period assuming a density of 3.0 gm//cm^(2) , typical of many planets, satellites, and asteroids. No such object is found to be spinning with a period shorter than found by this analysis.

The fastest possible of rotation of a planet is that for which the gravitational force on material at the equtor barely provides the centripetal force needed for the rotation. Show then that the corresponding shortest period of rotation is given by T=sqrt((3pi)/(Grho)) where rho is the density of the planet, assumed to be homogeneous. Evalute the rotation period assuming a density of 3.0 gm//cm^(2) , typical of many planets, satellites, and asteroids. No such object is found to be spinning with a period shorter than found by this analysis.