In a biprism experiement, by using light of wavelength `5000Å`, `5mm` wide fringes are obtained on a screen `1.0m` away from the coherent sources. The separation between the two coherent sources is

A biprism is placed 5 cm from slit illuminated by sodium light of wavelength 5890 overset (@)(A) The width of the fringes obtained on a screen 75cm from the biprism is 9.424 xx 10^-2 cm . What is the distance between two coherent sources ?

In a Young's double slit experiment, the separation between the slits is 0.15 mm. In the experiment, a source of light of wavelength 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is

In a biprism experiment, the slit is illuminated with light of wavelength 5000Å . The number of bright fringes passing on a screen, if the path difference is changed by 0.005cm will be

In Young's double-slit experiment using lambda=6000 Å , distance between the screen and the source is 1m. If the fringe-width on the screen is 0.06 cm, the distance between the two coherent sources is

In Fresnel's biprism experiment the width of 10 fringes is 2cm which are formed at a distance of two 2meter from the silt .If the wavelength of light is 5100Å then the distance between two coherent sources will be

In Young's double slit experiment the slits apart by 3 mm are illuminated with a source of monochromatic light of wavelength 6000 Å. Interference fringes are obtained on a screen at a distance of 1 m from the slits . The width of the fringe will be

In a Biprism experiment, the slit separation is 1mm. Using monochromatic light of wavelength 5000 Å, an interference patternn is obtained on a screen. For changing the bond width by 2.5xx10^(-5) m.

In a Fresnel's biprism experiment, sodium light of wavelength 5832 Å is used. Calculated the fringe width, given the distance between the screen and the biprism =120 cm and the distance the two sources=0.04 cm.