[" 60."int(0)^( pi/2)(sin x)/(sin x+cos ...

[" 60."int_(0)^( pi/2)(sin x)/(sin x+cos x)dx=?],[[" (A) "(pi)/(4)," (B) "(pi)/(2)]]

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int_(0)^((pi)/(2))(x)/(sin x+cos x)dx

int_(0)^(pi//2) (sinx )/(sin x + cos x ) dx=

int_(0)^( pi/2)(sin x)/(1+cos x)dx

int_(0)^((pi)/(2))(sin^(2)x)/(sin x+cos x)dx

int_(0)^( pi/2)(sin x-cos x)/(1+sin x*cos x)*dx

int_(0)^(pi//2)(sin x - cos x)/(1-sin x cos x)dx=

Prove that: int_(0)^( pi/2)(sin x)/(sin x-cos x)dx=(pi)/(4)

int_(0)^(pi) dx/(3+2sin x + cos x) =

int_(0) ^(pi//2) (sin x) /(sin x + cos x )^(2)dx=

int_(0)(pi//2) ( x dx)/(Sin x + Cos x)=

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