यदि ` ( 3 ) /( 2 + cos theta + i sin theta ) = a + ib ` तो सिद्ध कीजिये कि ` a ^ 2 + b ^ 2 = 4a - 3 `.

if 3/(2+cos theta+i sin theta)=a+ib then prove that a^2+b^2=4a-3

if (3)/(2+cos theta+i sin theta)=a+ib then (a-2)^(2)+b^(2) equals to:

If a cos theta + b sin theta =4 and a sin theta- b cos theta = 3 " then" a^(2) + b^(2) is equal to

if (3)/(2+cos theta+i sin theta)=a+ib then prove that a^(2)+b^(2)=4a-3

if (3)/(2+cos theta+i sin theta)=a+ib then prove that a^(2)+b^(2)=4a-3

(sin theta_ (1) + i cos theta_ (1)) (cos theta_ (2) + i sin theta_ (2)) ...... (sin theta_ (n) + i cos theta_ (n)) = a + ib, a ^ (2) + b ^ (2) =

If sin theta + cos theta = a and sin^(3) theta + cos^(3) theta = b, (3a - 2b)=

If (3)/(2+cos theta+i sin theta)=a+ib and a^(2)+b^(2)=a lambda-3, then the value of lambda, is

If a cos theta+b sin tan theta=3 and a sin theta-b cos theta=4, then a^(2)+b^(2) has the value