A vessel contains `110 g` of water. The heat capacity of the vessel is equal to `10 g` of water. The initial temperature of water in vessel is `10^(@)C`. If `220 g` of ho, water at `70^(@)C` is poured in the vessel, the final temperature neglecting radiation loss, will be

A beaker contains 200 g of water. The heat capacity of the beaker is equal to that of 20 g of water. The initial temperature of water in the beaker is 20^@C .If 440 g of hot water at 92^@C is poured in it, the final temperature (neglecting radiation loss) will be nearest to

A beaker contains 200 g of water. The heat capacity of the beaker is equal to that of 20 g of water. The initial temperature of water in the beaker is 20^@C .If 440 g of hot water at 92^@C is poured in it, the final temperature (neglecting radiation loss) will be nearest to

A beaker contains 200 gm of water. The heat capacity of the beaker is equal to that of 20 gm of water. The initial temperature of water in the beaker is 20^@C . If 440 gm of hot water at 92^@C is poured in it. the final temperature (neglecting radiation loss) will be nearest to

If 10 g of ice at 0^@C mixes with 10 g of water at 10^@C , then the final temperature t is given by

Initially , a bearker has 100 g of water at temperature 90^@C Later another 600 g of water at temperatures 20^@C was poured into the beaker. The temperature ,T of the water after mixing is

50 g ice at 0^(@)C in kept in an insulating vessel and 50 g water at 100^(@)C is mixed in it. Then the final temperature of the mixture is (neglect the heat loss)