A body is thrown vertically upwards with a velocity of `98 m//s`. If `g = 9.8 m//s^(2)`, when will it reach its highest point ? What will be its maximum height ?

An object is thrown vertically upwards with an initial velocity of 40 "m.s"^(-1) . (i) How long will the object move upwards? (ii) What will be the maximum height attained? (iii) How much time will it taken to reach the ground ? (iv) When will the object be at a height of 25 m from the ground ? (v) What will be its velocity after 2 s? [ g= 9.8 "m.s"^(-2)] .

A body is throw vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body.

A ball is thrown vertically upwards from the ground with a velocity of 24.5 m/s . If g=9.8 m/s^2 , then the ball will be at a height of 29.4 metres from the ground after time

A body is projected upwards with a velocity of 19.6 m/s. Find the time of ascend. G = 9.8 m / s^2 .

A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g= 10 m//s^2 , find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

A ball is thrown vertically upwards with a velocity of 4.9m/s Find (i) the maximum height reached by the ball (ii) time taken to reach the maximum height