If roots of the equation `ax^2 + bx + c = 0` are `alpha/(alpha-1)` and `(alpha+1)/alpha` and then `(a+b+c)^2` equals

If alpha and beta are roots of the equation ax^2+bx+c =0 and, if px^2+qx+r =0 has roots (1-alpha)/alpha and (1-beta)/beta , then r is equal is

If alpha,beta are the roots of the equation ax^(2)+bx+c=0, then (alpha)/(alpha beta+b)+(beta)/(a alpha+b) is equal to -

I a, b and c are not all equal and alpha and beta be the roots of the equation ax^(2) + bx + c = 0 , then value of (1 + alpha + alpha^(2)) (1 + beta + beta^(2)) is

If alpha, beta are the roots of the equation ax ^(2) + bx + c =0, then the value of (1)/( a alpha + b) + (1)/( a beta + b) equals to : a) (ac)/(b) b) 1 c) (ab)/(c) d) (b)/(ac)

If the roots of the equation ax^2+bx+c=0 are alpha and beta then show that 1/(a alpha+b)+1/(abeta+b)=b/(ac) .