A particle of mass m moves from A to C under the action of force `vecF = 2xyhati + y^2 hatj` , along different paths as shown in figure.

A particle of mass 1 kg is moved under the action of a force and velocity time graph of the particle is shown in figure.Work done by the force from t=0 to t=6 s Is

Four particles each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is :

Particle moves from point A to point B along the line shown in figure under the action of force. VecF = - x hati + y hatj . Determine the work done on the particle by vec F in moving the particle from point A to point B.

A particle moves along a circular path under the action of a force. The work done by the force is

A particle moves under the action of a force F=20hati + 15hatj along a straight line 3y + alphax =5 , where, alpha is a constant. If the work done by the force F is zero the value of alpha is .

A particle moves under the action of a force F=20hati + 15hatj along a straight line 3y + alphax =5 , where, alpha is a constant. If the work done by the force F is zero the value of alpha is .

Particle moves from point A to point B along the line shown in figure under the action of force. evc F = - x hati + y hatj . Determine the work done on the particle by vec F in moving the particle from point A to point B.