4x - (3y - x + 2z)

In a triangle XYZ, let x,y,z be the lengths of sides opposite to the angles X, Y, Z, respectively, and 2s = x + y + z . " If" (s - x)/4 = (x - y)/3 = (x - z)/2 and area o incircle of the triangle XYZ is (8pi)/3 , then

3x - [4y - {7x - (3z - 2y) + 4z - 3(x + 3y - 2z)}]

If (x,y,z) is the solution of the equations x - y - 2z = 3 2x + y + 4z = 5 4x - y - 2z = 11 then the value ofy equals

Add : 8x - 3y + 7z, -4x + 5y - 4z, -x - y - 2z

Use matrix methocd to solve the following system of equations: {:(4x + 2y + 3z = 2),(x + y + z = 1),(3x + y - 2z = 5):}

If (x,y,z) is the solution of the equations 4x + y = 7 3y + 4z = 5 5x + 3z = 2 Then the value of x + y + z equals

If x : y : z = 3 : 4 : 9, then what will be the value of (2x + 3y + z) : (2z + x – 3y)?