A slit of width a is illuminiated by white light. The first diffraction minimum for light of `lamda=6500 `Å is formed at `theta=30^(@)`, then the width (a) of the slit is

A slit of width is illuminated by white light. For red light (lambda=6500Å) , the first minima is obtained at theta=30^@ . Then the value of will be

A slit of width is illuminated by white light. For red light (lambda=6500Å) , the first minima is obtained at theta=30^@ . Then the value of will be

A slit of width a is illuminated by white light. For red light (lambda=6500Å) , the first minima is obtained at theta=30^@ . Then the value of a will be

A slit of width a is illuminated by red light of wavelength 650 nm. The first diffraction minimum is observed at an angle theta_(1) = 5.2^(@) from the direction of the incident beam. The width of the slit a in mm is

A slit of width a is illuminated by white light. (a) For what value of a will the first minimum for red light of wavelength lambda = 650 nm appear at theta= 15^(@) ?

First diffraction minima due to a single slit of width 10^-4 cm is at theta=30^@ . The wavelength of the light used is –

First diffraction minima due to a single slit of width 10^-4 cm is at theta=30^@ . The wavelength of the light used is –

A slit of width a illuminated by red light of wavelength 6500 Å . The first minimum will fall at theta=30^(@) if a is