6x^(2)-16x-21=

Find by factorization method: 6x^(2)-5x-21=0

When x^(5)-5x^(4)+9x^(3)-6x^(2)-16x+13 is divided by x^(2)-3x+a , then quotient and remainders are x^(3)-2x^(2)+x+1 and -15x+11 respectively . Find the value of a .

(3,-4) is the point to which the origin is shifted and the transformed equation is X^(2)+Y^(2)=4 then the original equation is (A) x^(2)+y^(2)+6x+8y+21=0 (B) x^(2)+y^(2)+6x+8y-21,=0 (C) x^(2)+y^(2)-6x+8y+21=0 (D) x^(2)+y^(2)-6x-8y+21=0

Divide 6x^(3)-26x-21+x^(2) by -7+3x .

factorize the given expression 6x^2-5x-21

factorize the given expression 5x^2-16x-21

x^(2)-6x=16

(16x^(2)-20x+9)/(8x^(2)+12x+21)=(4x-5)/(2x+3)

If the polynomial x^(4)-6x^(3)-16x^(2)+25x+10 is divided by another polynomial x^(2)-2x+k , the remainder comes out to be x+a , find k and a.

If the polynomial x^(4)-6x^(3)-16x^(2)+25x+10 is divided by another polynomial x^(2)-2x+k , the remainder comes out to be x+a , find k and a.