NaCl" is doped with "2times10^(-3)mol%SrCl_(2)," the concentration of cation vacancies is "

NaCl is doped with 2xx10^(-3) mol % SrCl_2 , the concentration of cation vacancies is

NaCl is doped with 2xx10^(-3) mol % SrCl_2 , the concentration of cation vacancies is

If NaCl is doped with 10^(-1)mol% of SrCl_(2) ,the concentration of cation vacancies will be "

If NaCl is doped with 10^(-4) mol % of SrCl_(2) , the concentration of cation vacancies will be ( N_(A) = 6.022 xx 10^(23) mol^(-1))

If NaCl is doped with 10^(-3) mol% SrCl_(2) , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-4)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))