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0.15 mole of pyridinium chloride has bee...

`0.15` mole of pyridinium chloride has been added into `500 cm^(3)` of `0.2M` pyridine solution. Calculate pH and hydroxyl ion contration in the resulting solution, assuming no change in volume. `(K_(b)"for pyridine" = 1.5xx10^(-9)M)`

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0.15 mole of pyridinium chloride has been added into 500 cm^(3) of 0.2 M pyridine solution. Calculate pH of the resulting solution, assuming no change in volume. (K, for pyridine = 1.5 xx 10^(-9) M)

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0.15 mol of pyridinium chloride is added to 500 mL 0.2 (M) pyridine solution. Determine the pH of the solution. Given: K_(b) (pyridine) =1.5xx10^(-9) and assume that volume of the solution does not change due to the addition of pyridinium chloride.