(tan alpha+tan beta)/(cot alpha+cot beta)=tan alpha tan beta

The expression (tan alpha+tan beta)cot(alpha+beta)+(tan alpha-tan beta)cot(alpha-beta) is independent of both alpha and beta.

(tan alpha + tan beta )/( tan (alpha + beta ))+(tan alpha - tan beta )/(tan (alpha - beta )) =

If (tanalpha+tanbeta)/(cot alpha+cot beta)+{cos(alpha-beta)+1}^(-1)=1, then tan alpha tan beta is equal to

If (tanalpha+tanbeta)/(cot alpha+cot beta)+{cos(alpha-beta)+1}^(-1)=1, then tan alpha tan beta is equal to

Prove that cos(alpha-beta)/(cos alpha sin beta)=tan alpha+cot beta

(no alpha + no beta) / (no alpha-no beta) = (tan ((alpha + beta) / (2))) / (tan ((alpha-beta) / (2)))

tan alpha=cot beta=a, find (alpha+beta)

(sec alpha * sec beta + tan alpha tan beta )^(2)-( sec alpha * tan beta + tan alpha * sec beta )^(2) =

Simplify be reducing to a single term : (tan alpha - tan ( alpha - beta))/(1 + tan alpha tan ( alpha - beta))