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In the preparation of CaO from CaCO(3) u...

In the preparation of CaO from `CaCO_(3)` using the equilibrium,
`CaCO_(3)(s) hArr CaO(s)+CO_(2)(g)`
`K_(p)` is expressed as
`log K_(p)=7.282-8500/T`
For complete decomposition of `CaCO_(3)`, the temperature in celsius to be used is:

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In preparation of CaO from CaCO_(3) using the equilibrium, CaCO_(3)(g)hArrCaO(s)+CO_(2)(g)K_(p) is expressed as log K_(p)=7.282-(8500)/(T) , where T is in Kelvin. What is value of K_(p) at a temperature of 1167 K?

In preparation of CaO from CaCO_(3) using the equilibrium, CaCO_(3)(g)hArrCaO(s)+CO_(2)(g)K_(p) is expressed as log K_(p)=7.282-(8500)/(T) , where T is in Kelvin. What is value of K_(p) at a temperature of 1167 K?

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