" (A) "cot(A)/(2)=(b+c)/(a)

If cot.(A)/(2)=(b+c)/(a) find angle B

If cot((A)/(2))=(b+c)/(a) then Delta ABC is

In triangle ABC, if (cot A)/(2)=(b+c)/(a), then triangle ABC must be

In any Delta ABC, prove that cot((A)/(2))+cot((B)/(2))+cot((C)/(2))=(a+b+c)/(b+c-a)cot((A)/(2))

In any triangle , prove that ((b-c)/( b+c)) cot ""(A)/(2) +((b+c)/(b-c)) tan ""(A)/(2) = 2 cosec (B-C)

If in triangle ABC,cot(A/2)=(b+c)/a, then the triangleABC is

r^(2) cot ""(A)/(2) cot ""(B)/(2) cot ""(C)/(2)

r("cot"(A)/(2)"cot"(B)/(2)"cot"(C)/(2))=

If A+B+C=pi , prove that (a) tan 3A+tan3B+tan3C=tan3A tan 3B tan 3C (b) cot""(A)/(2)+cot""(B)/(2)+cot""(C)/(2)=cot""(A)/(2)cot""(B)/(2)cot""(C)/(2)