If force `F` is increasing with time and at `t = 0, F = 0`, where will slipping first start?

A particle is resting over a smooth horizontal floor. At t=0 , a horizontal force starts acting on it. Magnitude of the force increases with the time according to law F=at , where 'a' is a constant. For figure which of the following statement is/are correct ?

A particle is resting over a smooth horizontal floor. At t = 0, a horizontal force starts acting on it. Magnitude of the force increases with time according to law F = alpha t, Where alpha is a positive constant. From figure, which of the following statements are correct ?

A particle is resting over a smooth horizontal floor. At t = 0, a horizontal force starts acting on it. Magnitude of the force increases with time according to law F = alpha t, Where alpha is a positive constant. From figure, which of the following statements are correct ?

A particle is resting over a smooth horizontal floor AT t = 0, a horizontal force starts acting on it. Magnitude of the force increases with time F = kt, where k is a constant. The two curves are drawn for this particle as shown

If force (F) is given by F = Pt^(-1) + alpha t, where t is time. The unit of P is same as that of

If force (F) is given by F = Pt^(-1) + alpha t, where t is time. The unit of P is same as that of

A bar of mass m_(1) is placed on a plank of mass m_(2) which rests on a smooth horizontal plane . The coefficient of friction between the surfaces of bar and plank is k . The plank is subjected to a horizontal force F depending on time t as F = at , where a is a constant . The moment of time t_(0) at which the plank starts sliding is :

A block is resting over a rough horizontal floor. At t = 0 a time -verying force starts acting on it , the force is described by equation F = kt where k is constant and r is in seconds Marks the cerrect statement (s) for this situation .

A block is resting over a rough horizontal floor. At t = 0 a time -verying force starts acting on it , the force is described by equation F = kt where k is constant and r is in seconds Marks the cerrect statement (s) for this situation .