A function f is defined such that `f(1)=2, f(2)=5, and f(n)=f(n-1)-f(n-2)` for all integer values of n greater than 2. What is the value of f(4)?

The function f: N to N defined by f(n) =2n+3 is

Given f(1)=2 and f(n+1)=(f(n)-1)/(f(n)+1)AA n in N then

If a function F is such that F(0)=2 , F(1)=3 , F(n+2)=2F(n)-F(n+1) for n ge 0 , then F(5) is equal to

If a function F is such that F(0)=2 , F(1)=3 , F(n+2)=2F(n)-F(n+1) for n ge 0 , then F(5) is equal to

Consider the function f defined on the set of all non-negative interger such that f(0) = 1, f(1) =0 and f(n) + f(n-1) = nf(n-1)+(n-1) f(n-2) for n ge 2 , then f(5) is equal to

Consider the function f defined on the set of all non-negative interger such that f(0) = 1, f(1) =0 and f(n) + f(n-1) = nf(n-1)+(n-1) f(n-2) for n ge 2 , then f(5) is equal to

If f is a function defined on the set of all non negative integers such that f(0)=1, f(1)=0 f(n)+f(n-1)=nf(n-1) +(n-1) f(n-2) " for "n ge 2 then f(5)=

A Function f is defined for all positive integers and satisfies f(1)=2005 and f(1)+f(2)+.........+f(n)=n^(2)f(n) for all n>1. Find the value of f(2004)

If f:NtoR is defined by f(1) = - 1 and f(n+1) = 3f(n) + 2 for nge1 , then f is