Find the length of seconds pendulum at a place where `g = pi^(2) m//s^(2)`.

Find the length of seconds pendulum at a place where g =4 pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = 10 m/s^2 .

Find the length of a second.s pendulum at a place where g=10 ms^(-2) (Take pi = 3.14)

Calculate the length of a seconds' pendulum at a place where g= 9.8 m s^(-2)

The length of seconds pendulum at a place wl}ere g = 4.9 m/ s^2 is

The length of seconds pendulum at a place wl}ere g = 4.9 m/ s^2 is

The length of a seconds pendulum at a place where g = 9.8 frac(m)(s^2) is 0.994m If the amplitude is 0.15m, its maximum velocity is

Calculate the length of asecond pendulam at a place where g= 9.8 ms^(-2) . [Hint: A seconds pendulam Is one with a time period of exactly 2 s]

Determine the length of a seconds pendulum at a place, where the acceleration due to gravity is 9.77 frac(m)(s^2)

Instantaneous angle (in radian) between string of a simple pendulum and verical is given by theta = (pi)/(180) sin2pit . Find the length of the pendulum if g = pi^(2) m//s^(2) .