Let f : (-1,1) `to` R be a differentiabale function with f(0) = -1 and f'(0) = 1. Let
g(x) = `[f(2f(x)+2)]^(2)` , then g'(0)=

Let f : (-1,1) to R be a differentiable function with f(0) = -1 and f'(0) = 1 . Let g(x) = [f(2f(x)+2)]^(2) , then g'(0)=

Let f : (-1, 1) to R be a differentiable function with f(0) = -1 and f'(0) = 1 . Let g(x) = [f(2f(x) + 2)]^2 . Then g'(0) is equal to

Let f: (-1,1) rarr R be a differentiable function with f(0) = -1 and f'(0) = 1 let g(x) =[f(2f(x)+2)]^2 , then g'(0) =

Let f : (-1,1) to R be a differentiable function with f(0) =-1 and f'(0)=1 Let g(x)= [f(f(2x)+1)]^2 . Then g'(0)=

Let f:(-1,1)toR be a differentiable function with f(0)=-1 and f'(0)=1 . Let g(x)=[f(2f(x)+2)]^(2) . Then g'(0)=