A particle is projected at angle `theta` from horizontal. The product of the two possible times it take to pass over the height `h (h lt H_("max"))` is

A particle is projected with a speed u at an angle theta to the horizontal. Find the radius of curvature. At the point where the particle is at a highest half of the maximum height H attained by it.

A particle is projected with a speed u at an angle theta to the horizontal. Find the radius of curvature. At the point where the particle is at a highest half of the maximum height H attained by it.

A particle is projected from ground at some angle with the horizontal. Let P be the point at maximum height H . At what height above the point P should the particle be aimed to have range equal to maximum height ?

A particle is projected vertically upwards and attains maximum height H. If the ratio of the times to attain heighth on two way journey t (h

A particle is projected with velocity 2sqrt(gh) and at an angle 60^@ to the horizontal so that it just clears two walls of equal height 'h' which are at a distance 2h from each other. The time taken by the particle to travel between these two walls

Particle is projected from the ground at a certain angle with horizontal . If particle takes time T to hit the ground again , then maximum height of the projectile is

A stone is thrown at an angle theta to the horizontal reaches a maximum height H. Then the time of flight of stone will be:

A stone is thrown at an angle theta to the horizontal reaches a maximum height H. Then the time of flight of stone will be: