Home
Class 12
PHYSICS
The period of small oscillations of a si...

The period of small oscillations of a simple pendulum of length `l` if its point of suspension `O` moves `a` with a constant acceleration `alpha = alpha_(1)overset(wedge)(i) - alpha_(2)overset(wedge)(j)` with respect to earth is (`overset(wedge)(i)` and `overset(wedge)(j)` are unit vectors in horizontal in horizontal and vertically upward directions respectively)

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the period of oscillation of a pendulum of length l if its point of suspension is (a) moving vertically up with acceleration a (b) moving vertically down with acceleration a(lt g) (c) failing freely under gravity moving horizontal with acceleration a .

Find the period of oscillation of a pendulum of length l if its point of suspension is (a) moving vertically up with acceleration a (b) moving vertically down with acceleration a(lt g) (c) failing freely under gravity moving horizontal with acceleration a .

A body of mass 5 kg is acted upon by a constant force vecF=(-3overset(wedge)(i)+6overset(wedge)(j))N Its initial velocity at t = 0 is vecu = (6overset(wedge)-2overset(wedge)ms^(-1) what is its velocity after 5s ? What is its magnitude ?

Find the period of small oscillations of a mathematical pendulum of length l if its point of suspension O moves relative to the Earth's surface in an arbitrary directio with a constant acceleration w (figure). Calculate that period if l=21 cm, w=g//2, and the angle between the vectors w and g equals beat =120^(@) .

A ball weighing 150g is moving with an initial velocity overline(u)=(3overset(wedge)(i)+4overset(wedge)(j))ms^(-1) After being hit by the player its final velocity is overline(u)=(3overset(wedge)(i)+4overset(wedge)(j))ms^(-1) What is the magnitude of change in momentam in kg ms^(-1)

The velocity of a body of mass 2 kg is given by vecupsilon=(2t overset(wedge)(i)+t^(2)overset(wedge)(j)) Find the momentum of the body after 2 seconds.

A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration alpha , then the time period is given by T = 2pisqrt(((I)/(T))) where g is equal to

A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration alpha , then the time period is given by T = 2pisqrt(((I)/(g))) where g is equal to

A projectile is given an initial velocity of (hat(i)+2hat(j)) The Cartesian equation of its path is (g = 10 ms^(-1)) ( Here , hati is the unit vector along horizontal and hatj is unit vector vertically upwards)